The removeAll() method of java.util.Set interface is used to remove from this set all of its elements that are contained in the specified collection.
Syntax:
public boolean removeAll(Collection c)
Parameters: This method takes collection c as a parameter containing elements to be removed from this set.
Returns Value: This method returns true if this set changed as a result of the call.
Exception: This method throws NullPointerException if this set contains a null element and the specified collection does not permit null elements (optional), or if the specified collection is null.
Below are the examples to illustrate the removeAll() method.
Example 1:
// Java program to demonstrate// removeAll() method for Integer value  import java.util.*;  public class GFG1 {    public static void main(String[] argv) throws Exception    {          try {            // Creating object of Set            Set<Integer> set1 = new HashSet<Integer>();              // Populating set1            set1.add(1);            set1.add(2);            set1.add(3);            set1.add(4);            set1.add(5);              // print set1            System.out.println("Set before removeAll() operation : "                               + set1);              // Creating another object of Set            Set<Integer> set2 = new HashSet<Integer>();            set2.add(1);            set2.add(2);            set2.add(3);              // print set2            System.out.println("Collection Elements to be removed : "                               + set2);              // Removing elements from set            // specified in set2            // using removeAll() method            set1.removeAll(set2);              // print set1            System.out.println("Set after removeAll() operation : "                               + set1);        }          catch (NullPointerException e) {            System.out.println("Exception thrown : " + e);        }    }} |
Output:
Set before removeAll() operation : [1, 2, 3, 4, 5] Collection Elements to be removed : [1, 2, 3] Set after removeAll() operation : [4, 5]
Example 2: For NullPointerException.
// Java program to demonstrate// removeAll() method for Integer value  import java.util.*;  public class GFG1 {    public static void main(String[] argv) throws Exception    {        try {              // Creating object of Set            Set<Integer> set1 = new HashSet<Integer>();              // Populating set1            set1.add(1);            set1.add(2);            set1.add(3);            set1.add(4);            set1.add(5);              // print set1            System.out.println("Set before removeAll() operation : "                               + set1);              // Creating another object of Set<Integer>            Set<Integer> set2 = null;              // print set2            System.out.println("Collection Elements to be removed : "                               + set2);              System.out.println("\nTrying to pass "                               + "null as a specified element\n");              // Removing elements from set            // specified in set2            // using removeAll() method            set1.removeAll(set2);              // print set1            System.out.println("Set after removeAll() operation : "                               + set1);        }          catch (NullPointerException e) {            System.out.println("Exception thrown : " + e);        }    }} |
Output:
Set before removeAll() operation : [1, 2, 3, 4, 5] Collection Elements to be removed : null Trying to pass null as a specified element Exception thrown : java.lang.NullPointerException
Reference: https://docs.oracle.com/javase/7/docs/api/java/util/Set.html#removeAll(java.util.Collection)
